Answer:
Option A
Explanation:
For dilute solutions, the elevation is boiling point is directly proportional to the molal concentration pf the solute in solution (m)
Thus, $\triangle T_{b}\propto m$
$\triangle T_{b}= k_{b}m$
where, kb is molal boiling point elevation constant
As, molality (m)= Moles of solute(n2) / Mass of solvent (W1)(in kg)
Moles of solute $(n_{2})= \frac{W_{2}}{M_{2}}$
$\therefore$ $\triangle T_{b}= \frac{k_{b}\times W_{2}}{M_{2}\times W_{1}}$
$\Rightarrow$ $ M_{2}= \frac{k_{b}. W_{2}}{\triangle T_{b}. W_{1}}$